An electron is revolving in a circular orbit | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The magnetic dipole moment '$M$' of an electron revolving in a circular orbit of radius '$r$' with velocity '$v$' is given by $M = IA$, where '$I$

Vedclass · Accepted Answer

$2mM/e$

Vedclass · Answer

(A) The magnetic dipole moment '$M$' of an electron revolving in a circular orbit of radius '$r$' with velocity '$v$' is given by $M = IA$, where '$I$' is the current and '$A$' is the area of the orbit.$I = e/T = ev / (2\pi r)$$A = \pi r^2$So, $M = (ev / 2\pi r) 	imes \pi r^2 = evr / 2$.The angular momentum '$L$' of the electron is $L = mvr$.From the expression for '$M$',we have $M = (e/2m) 	imes (mvr) = (e/2m) 	imes L$.Rearranging for '$L$',we get $L = 2mM / e$.

An electron is revolving in a circular orbit of radius '$r$' in a hydrogen atom. Using Bohr's theory, the angular momentum of the electron is (where '$M$' = magnetic dipole moment,'$m$' = mass of electron,'$e$' = charge of electron).

Similar Questions

The velocity of an electron in the second orbit of a sodium atom (atomic number $Z = 11$) is $v$. The velocity of an electron in its fifth orbit will be

The angular momentum of the orbital electron is an integral multiple of:

When an electron jumps from the orbit $n=2$ to $n=4$,the wavelength of the radiation absorbed will be ($R$ is Rydberg's constant).

The ratio of radii of $3^{\text{rd}}$ and $6^{\text{th}}$ Bohr's orbit in a hydrogen atom is

$A$ sample of hydrogen atoms in its ground state is radiated with photons of $10.2 eV$ energy. The radiation emitted from the sample is absorbed by excited ionized $He^{+}$ ions. Which of the following statement$(s)$ is/are true?

Vedclass Test Series

Exam Paper Generator

Online Exam Module