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(B) For a hydrogen-like atom, the energy levels are given by $E_n = -13.6 Z^2 / n^2 	ext{ eV}$.As the electron transitions from an excited state $(n

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$K$.$E$. increases, but $P$.$E$. and $T$.$E$. decrease.

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(B) For a hydrogen-like atom, the energy levels are given by $E_n = -13.6 Z^2 / n^2 	ext{ eV}$.As the electron transitions from an excited state $(n > 1)$ to the ground state $(n = 1)$, the principal quantum number $n$ decreases.$1$. Total Energy $(T.E.)$: Since $T.E. = -13.6 Z^2 / n^2$, as $n$ decreases, the magnitude of $T.E.$ increases, meaning the value becomes more negative. Thus, $T.E.$ decreases.$2$. Potential Energy $(P.E.)$: We know $P.E. = 2 	imes T.E. = -27.2 Z^2 / n^2$. As $n$ decreases, the magnitude of $P.E.$ increases, making it more negative. Thus, $P.E.$ decreases.$3$. Kinetic Energy $(K.E.)$: We know $K.E. = -T.E. = 13.6 Z^2 / n^2$. As $n$ decreases, $K.E.$ increases.Therefore, $K.E.$ increases, while $P.E.$ and $T.E.$ decrease.

An electron makes a transition from an excited state to the ground state of a hydrogen-like atom. Out of the following statements, which one is correct?

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