An electron revolves in a circle of radius 0. | vedclass

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(C) Given: radius $r = 0.4 	ext{ Å} = 0.4 	imes 10^{-10} 	ext{ m}$, speed $v = 10^6 	ext{ m/s}$, charge $q = 1.6 	imes 10^{-19} 	ext{ C}$.The mo

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$10$

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(C) Given: radius $r = 0.4 	ext{ Å} = 0.4 	imes 10^{-10} 	ext{ m}$, speed $v = 10^6 	ext{ m/s}$, charge $q = 1.6 	imes 10^{-19} 	ext{ C}$.The moving electron constitutes an electric current $i$ given by $i = \frac{q}{T}$, where $T$ is the time period.Since $T = \frac{2\pi r}{v}$, we have $i = \frac{qv}{2\pi r}$.Substituting the values:$i = \frac{1.6 	imes 10^{-19} 	imes 10^6}{2\pi 	imes 0.4 	imes 10^{-10}} = \frac{1.6 	imes 10^{-13}}{0.8\pi 	imes 10^{-10}} = \frac{2 	imes 10^{-3}}{\pi} 	ext{ A}$.The magnetic field $B$ at the center of a circular current loop is $B = \frac{\mu_0 i}{2r}$.Substituting the values:$B = \frac{4\pi 	imes 10^{-7}}{2 	imes 0.4 	imes 10^{-10}} 	imes \frac{2 	imes 10^{-3}}{\pi} = \frac{4\pi 	imes 10^{-7} 	imes 2 	imes 10^{-3}}{0.8\pi 	imes 10^{-10}} = \frac{8\pi 	imes 10^{-10}}{0.8\pi 	imes 10^{-10}} = 10 	ext{ T}$.

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