An element with atomic number 84 and mass num | vedclass

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(A) Let the element be $X$. The initial state is $_{84}X^{218}$.When an element emits one $\alpha$-particle $(_{2}He^{4})$,the atomic number decreases

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Atomic number $84$ and mass number $214$

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(A) Let the element be $X$. The initial state is $_{84}X^{218}$.When an element emits one $\alpha$-particle $(_{2}He^{4})$,the atomic number decreases by $2$ and the mass number decreases by $4$.After $1$ $\alpha$-emission: $_{84-2}X^{218-4} = _{82}X^{214}$.When an element emits one $\beta$-particle $(_{-1}e^{0})$,the atomic number increases by $1$ and the mass number remains unchanged.After $2$ $\beta$-emissions: $_{82+(2 	imes 1)}X^{214} = _{84}X^{214}$.Thus,the final element has atomic number $84$ and mass number $214$.

An element with atomic number $84$ and mass number $218$ loses one $\alpha$-particle and two $\beta$-particles in three successive stages. The resulting element will have:

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