An ellipsoidal cavity is carved within a perfect conductor. $A$ positive charge $q$ is placed at the centre of the cavity. The points $A$ and $B$ are on the cavity surface as shown in the figure. Then

  • A
    Electric field near $A$ in the cavity = Electric field near $B$ in the cavity
  • B
    Total electric field flux through the surface of the cavity is $q/{\varepsilon _0}$
  • C
    Potential at $A = $ Potential at $B$
  • D
    Both $(b)$ and $(c)$

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