An engineering student has to secure 25 % mar | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To pass the examination,a student needs to secure $25 \%$ of the maximum marks.Given that the student obtained $47$ marks and failed by $43$ marks

Vedclass · Accepted Answer

$360$

Vedclass · Answer

(B) To pass the examination,a student needs to secure $25 \%$ of the maximum marks.Given that the student obtained $47$ marks and failed by $43$ marks,the passing marks can be calculated as:$	ext{Passing Marks} = 47 + 43 = 90$.Since $25 \%$ of the maximum marks is equal to $90$,we can set up the equation:$0.25 	imes 	ext{Maximum Marks} = 90$.$	ext{Maximum Marks} = \frac{90}{0.25} = 90 	imes 4 = 360$.Therefore,the maximum marks of the examination are $360$.

An engineering student has to secure $25 \%$ marks to pass. He gets $47$ marks and fails by $43$ marks. What are the maximum marks of the examination?

Similar Questions

$45 \%$ of $1500 + 35 \%$ of $1700 = ? \%$ of $3175$

If $A$'s salary is $30\%$ more than that of $B$,then by how much percent is $B$'s salary less than that of $A$ (in $\%$)?

$A$ student has to secure $15\%$ marks to pass the examination. If he gets $80$ marks and fails by $70$ marks,find the maximum marks set for the examination.

An inspector rejects $0.08 \%$ of the meters as defective. How many will he examine to reject $2$?

If $18 \%$ of a number is $720,$ then what is $81 \%$ of the same number?

Vedclass Test Series

Exam Paper Generator

Online Exam Module