An ether (A),C_5H_{12}O,when heated with exce | vedclass

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(A) The ether $(A)$ has the molecular formula $C_5H_{12}O$. Reaction with excess $HI$ produces two alkyl halides. Treatment of these alkyl halides wit

Vedclass · Accepted Answer

$2-$ethoxypropane

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(A) The ether $(A)$ has the molecular formula $C_5H_{12}O$. Reaction with excess $HI$ produces two alkyl halides. Treatment of these alkyl halides with $NaOH$ yields alcohols $(B)$ and $(C)$. Oxidation of $(B)$ produces propanone $(CH_3COCH_3)$,which indicates that $(B)$ is propan-$2$-ol $(CH_3CH(OH)CH_3)$. Oxidation of $(C)$ produces ethanoic acid $(CH_3COOH)$,which indicates that $(C)$ is ethanol $(CH_3CH_2OH)$. Therefore,the ether $(A)$ is formed by the combination of an isopropyl group and an ethyl group,which is $CH_3CH_2OCH(CH_3)_2$. The $IUPAC$ name of this ether is $2-$ethoxypropane.

An ether $(A)$,$C_5H_{12}O$,when heated with excess of hot concentrated $HI$ produced two alkyl halides which when treated with $NaOH$ yielded compounds $(B)$ and $(C)$. Oxidation of $(B)$ and $(C)$ gave a propanone and an ethanoic acid respectively. The $IUPAC$ name of the ether $(A)$ is

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