An ideal gas at temperature T, pressure p occ | vedclass

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(A) Given, initial temperature, pressure, and volume of an ideal gas are $T_1 = T$, $p_1 = p$, and $V_1 = V$.Final temperature, pressure, and volume a

Vedclass · Accepted Answer

$V/4$

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(A) Given, initial temperature, pressure, and volume of an ideal gas are $T_1 = T$, $p_1 = p$, and $V_1 = V$.Final temperature, pressure, and volume are $T_2 = T/2$, $p_2 = 2p$, and $V_2 = ?$.According to the ideal gas equation, $\frac{p_1 V_1}{T_1} = \frac{p_2 V_2}{T_2}$.Substituting the values, we get $\frac{p 	imes V}{T} = \frac{2p 	imes V_2}{T/2}$.Simplifying the equation: $\frac{pV}{T} = \frac{4p V_2}{T}$.Canceling $p$ and $T$ from both sides, we get $V = 4 V_2$.Therefore, the new volume is $V_2 = V/4$.

An ideal gas at temperature $T$, pressure $p$ occupies a volume $V$. If its temperature is halved and pressure doubled, what is its new volume?

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