An ideal gas follows a process described by p | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given the process equation: $p V^2 = C$.For an ideal gas,we know that $p V = n R T$,which implies $p = \frac{n R T}{V}$.Substituting this into the

Vedclass · Accepted Answer

if $V_2 > V_1$ then $T_2 < T_1$

Vedclass · Answer

(B) Given the process equation: $p V^2 = C$.For an ideal gas,we know that $p V = n R T$,which implies $p = \frac{n R T}{V}$.Substituting this into the process equation:$\left(\frac{n R T}{V}ight) V^2 = C$$n R T V = C$Since $n, R,$ and $C$ are constants,we have $T V = 	ext{constant}$,or $T \propto \frac{1}{V}$.If $V_2 > V_1$,then according to the relation $T \propto \frac{1}{V}$,the temperature $T_2$ must be less than $T_1$ $(T_2 Therefore,option $(b)$ is correct.

An ideal gas follows a process described by $p V^2 = C$ from $(p_1, V_1, T_1)$ to $(p_2, V_2, T_2)$,where $C$ is a constant. Then,

Similar Questions

One mole of an ideal monatomic gas undergoes a process described by the equation $PV^3 = \text{constant}$. The heat capacity of the gas during this process is

The specific heat of a gas in a polytropic process is given by

One mole of an ideal monoatomic gas at temperature $T_0$ expands slowly according to the law $P/V = \text{constant}$. If the final temperature is $2 T_0$, heat supplied to the gas is:

An ideal gas follows a process described by the equation $PV^2 = C$ from the initial $(P_1, V_1, T_1)$ to final $(P_2, V_2, T_2)$ thermodynamic states,where $C$ is a constant. Then:

Hydrogen gas is undergoing a process given by $PV^2 = \text{constant}$. The ratio of work done by the gas to the change in its internal energy is

Vedclass Test Series

Exam Paper Generator

Online Exam Module