An ideal gas follows the path shown in the figure. The net work done in the whole cycle is

$A$ thermodynamic system is taken from an original state $D$ to an intermediate state $E$ by the linear process shown in the figure. Its volume is then reduced to the original volume from $E$ to $F$ by an isobaric process. The total work done by the gas from $D$ to $E$ to $F$ will be $......J$

$A$ thermodynamic process is shown in the figure. The pressure and volume at the points shown in the figure are as follows:
$P_A = 3 \times 10^{4} \text{ Pa}, V_A = 2 \times 10^{-3} \text{ m}^3, P_B = 8 \times 10^{4} \text{ Pa}, V_D = 5 \times 10^{-3} \text{ m}^3.$
In process $AB$, $600 \text{ J}$ of heat is added to the system, and in process $BC$, $200 \text{ J}$ of heat is added. The change in internal energy during the process $AC$ is: (in $\text{ J}$)

$A$ thermodynamic system is taken through the closed cycle $PQRSP$ process as shown in the figure. The net work done by the system is ...... $J$.

$A$ mole of an ideal diatomic gas undergoes a transition from $A$ to $B$ along a path $AB$ as shown in the figure. The change in internal energy of the gas during the transition is ...... $kJ$.

An ideal gas is taken from state-$1$ to state-$2$ through paths $A, B, C$ and $D$ as shown in the $P-V$ diagram. Let $Q, W$ and $\Delta U$ represent the heat supplied,work done,and change in internal energy respectively. Then: