An ideal gas undergoes a cyclic process ABCDA | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The work done by the gas in a cyclic process is equal to the area enclosed by the $p-V$ loop.In the given $p-V$ diagram, the process $ABCDA$ forms

Vedclass · Accepted Answer

$4P_0V_0$

Vedclass · Answer

(B) The work done by the gas in a cyclic process is equal to the area enclosed by the $p-V$ loop.In the given $p-V$ diagram, the process $ABCDA$ forms a rectangle.The area of the rectangle is given by $	ext{Area} = 	ext{width} 	imes 	ext{height}$.The width of the rectangle along the $V$-axis is $(5V_0 - 3V_0) = 2V_0$.The height of the rectangle along the $p$-axis is $(4P_0 - 2P_0) = 2P_0$.Therefore, the magnitude of the work done is $	ext{Area} = (2V_0) 	imes (2P_0) = 4P_0V_0$.Since the cycle is traversed in a clockwise direction, the work done by the gas is positive.

An ideal gas undergoes a cyclic process $ABCDA$ as shown in the given $p-V$ diagram. What is the magnitude of the amount of work done by the gas?

Similar Questions

$A$ gas goes from state $A$ to state $B$ via three different paths as shown in the $P-V$ diagram. If $Q_1, Q_2,$ and $Q_3$ are the heat absorbed by the gas along the three paths, then:

The $P-V$ diagram of an ideal gas is as shown in the figure. The work done by the gas in the process $ABCD$ is:

The heat energy absorbed by a system in going through a cyclic process shown in the figure is:

What is the total work done in the given $P-V$ graph?

One mole of an ideal diatomic gas undergoes a transition from $A$ to $B$ along a path $AB$ as shown in the figure. The change in internal energy of the gas during the transition is ............ $kJ$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module