An inductive circuit contains a resistance of $10 \, \Omega$ and an inductance of $20 \, H$. If an $AC$ voltage of $120 \, V$ and frequency $60 \, Hz$ is applied to this circuit, the current would be nearly: (in $A$)

In a series $LCR$ circuit,the voltages across the capacitor,resistor,and inductor are in the ratio $2:3:6$. If the voltage of the ac source in the circuit is $240 \ V$,then the voltage across the inductor is (in $V$)

When a $60 \text{ mH}$ inductor and a resistor are connected in series with an $AC$ voltage source, the voltage leads the current by $60^{\circ}$. If the inductor is replaced by a $0.5 \text{ } \mu\text{F}$ capacitor, the voltage lags behind the current by $30^{\circ}$. What is the frequency of the $AC$ supply?

$A$ current of $\frac{25}{\pi} \text{ Hz}$ frequency is passing through an $AC$ circuit having a series combination of $R=100 \ \Omega$ and $L=2 \text{ H}$. The phase difference between voltage and current is . . . . . . . (in $^{\circ}$)

In an $A.C.$ circuit,a resistance '$R$' is connected in series with an inductance '$L$'. If the phase angle between voltage and current is $45^{\circ}$,the value of inductive reactance will be $(\tan 45^{\circ} = 1)$.

When a $DC$ voltage of $100 \, V$ is applied to an inductor, a $DC$ current of $5 \, A$ flows through it. When an $AC$ voltage of $200 \, V$ peak value is connected to the inductor, its inductive reactance is found to be $20\sqrt{3} \, \Omega$. The power dissipated in the circuit is . . . . . . $W$.