An inductor and a resistor in series are conn | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In a pure inductor,the current lags behind the potential difference across the inductor by a phase angle of $\pi/2$ radians (or $90^{\circ}$).This

Vedclass · Accepted Answer

go on increasing

Vedclass · Answer

(D) In a pure inductor,the current lags behind the potential difference across the inductor by a phase angle of $\pi/2$ radians (or $90^{\circ}$).This phase relationship is independent of the frequency of the $A.C.$ source.Therefore,the phase angle between the current and the potential difference across the inductor $L$ remains constant at $90^{\circ}$ regardless of the change in frequency.However,if the question refers to the phase angle $\phi$ of the entire $LR$ series circuit,it is given by $	an \phi = \frac{X_L}{R} = \frac{\omega L}{R} = \frac{2\pi f L}{R}$.As the frequency $f$ increases,$	an \phi$ increases,and thus the phase angle $\phi$ between the source voltage and current increases.Given the specific phrasing 'phase angle between current and the potential difference across $L$',the answer is that it remains constant. Since this is not an option,the question likely intends to ask for the phase angle of the circuit,which increases as frequency increases.

An inductor and a resistor in series are connected to an $A.C.$ supply of variable frequency. As the frequency of the source is increased,the phase angle between current and the potential difference across $L$ will

Similar Questions

In an $LCR$ series $a.c.$ circuit,the voltage across each of the components $L, C$ and $R$ is $60 \,V$. The voltage across the $LC$ combination is

In a given series $LCR$ circuit,$R = 4\, \Omega, X_L = 5\, \Omega$ and $X_C = 8\, \Omega$. The current :-

In the given figure,the current amplitude is

Vedclass Test Series

Exam Paper Generator

Online Exam Module