An infinitely long straight conductor is bent | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnetic field at the centre $O$ is the vector sum of the magnetic field due to the straight wire and the magnetic field due to the circular l

Vedclass · Accepted Answer

$\frac{\mu_0 I}{2 \pi R}(\pi+1)$

Vedclass · Answer

(C) The magnetic field at the centre $O$ is the vector sum of the magnetic field due to the straight wire and the magnetic field due to the circular loop.$1$. Magnetic field due to the straight wire at distance $R$ from the centre $O$:$B_1 = \frac{\mu_0 I}{2 \pi R}$ (directed outwards,perpendicular to the plane).$2$. Magnetic field due to the circular loop of radius $R$ at its centre $O$:$B_2 = \frac{\mu_0 I}{2 R}$ (directed outwards,perpendicular to the plane).Since both magnetic fields are in the same direction (outwards),the resultant magnetic field $B$ is:$B = B_1 + B_2$$B = \frac{\mu_0 I}{2 \pi R} + \frac{\mu_0 I}{2 R}$$B = \frac{\mu_0 I}{2 \pi R} (1 + \pi)$Thus,the magnitude of the magnetic induction at the centre is $\frac{\mu_0 I}{2 \pi R}(\pi+1)$.

An infinitely long straight conductor is bent into the shape as shown below. It carries a current of $I$ ampere and the radius of the circular loop is $R$ metre. Then,the magnitude of magnetic induction at the centre of the circular loop is

Similar Questions

In a transformer,the number of turns in the primary coil is $140$ and that in the secondary coil is $280$. If the current in the primary coil is $4 \, A$,then the current in the secondary coil is......$A$.

Carborundum is

Assertion : Yeasts such as $Saccharomyces \text{ } cerevisiae$ are used in baking industry.
Reason : Carbon dioxide produced during fermentation causes bread dough to rise by thermal expansion.

Which was the first inorganic pesticide developed on a commercial scale?

Vedclass Test Series

Exam Paper Generator

Online Exam Module