An inorganic compound X on treatment with con | vedclass

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(A) $1$. The brown fumes produced with concentrated $H_{2}SO_{4}$ and the formation of a dark brown ring with $FeSO_{4}$ indicate the presence of the

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$Cu(NO_{3})_{2}$

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(A) $1$. The brown fumes produced with concentrated $H_{2}SO_{4}$ and the formation of a dark brown ring with $FeSO_{4}$ indicate the presence of the nitrate ion $(NO_{3}^{-})$ in compound $X$.$2$. The formation of a precipitate $Y$ when the solution of $X$ in dilute $HCl$ is treated with $H_{2}S$ gas indicates the presence of a Group-$II$ cation. Among the options,$Cu^{2+}$ is a Group-$II$ cation that forms a black precipitate $(CuS)$ with $H_{2}S$.$3$. The precipitate $CuS$ $(Y)$ dissolves in concentrated $HNO_{3}$ to form $Cu(NO_{3})_{2}$.$4$. Adding excess $NH_{4}OH$ to the $Cu(NO_{3})_{2}$ solution forms the deep blue complex $[Cu(NH_{3})_{4}]^{2+}$.$5$. Therefore,compound $X$ is $Cu(NO_{3})_{2}$.

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