An ion M^{2+} forms the complexes [M(H_2O)_6] | vedclass

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(B) The crystal field splitting energy $\Delta_{o}$ is directly proportional to the energy of the absorbed light and inversely proportional to the wav

Vedclass · Accepted Answer

Blue,red and green

Vedclass · Answer

(B) The crystal field splitting energy $\Delta_{o}$ is directly proportional to the energy of the absorbed light and inversely proportional to the wavelength of the absorbed light. Stronger ligands cause larger splitting,resulting in higher energy and shorter wavelength absorption. The order of ligand field strength is $Br^{-} Consequently,the wavelength of light absorbed follows the order: $[MBr_6]^{4-} > [M(H_2O)_6]^{2+} > [M(en)_3]^{2+}$. Based on the complementary colour wheel,the observed colours for these complexes are $[M(H_2O)_6]^{2+}$ (blue),$[M(en)_3]^{2+}$ (red),and $[MBr_6]^{4-}$ (green). Thus,the correct matching is blue,red,and green. Therefore,option $B$ is correct.

An ion $M^{2+}$ forms the complexes $[M(H_2O)_6]^{2+}$,$[M(en)_3]^{2+}$,and $[MBr_6]^{4-}$. Match the complex with the appropriate colour.

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