An ion with mass number 56 contains 3 units o | vedclass

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(A) Let the number of electrons in the ion $A^{3+}$ be $x$.Number of neutrons $= x + 0.304x = 1.304x$.For a tripositive ion $A^{3+}$,the number of pro

Vedclass · Accepted Answer

$_{26}^{56} Fe^{3+}$

Vedclass · Answer

(A) Let the number of electrons in the ion $A^{3+}$ be $x$.Number of neutrons $= x + 0.304x = 1.304x$.For a tripositive ion $A^{3+}$,the number of protons $= x + 3$.Mass number $= 	ext{Protons} + 	ext{Neutrons} = 56$.$(x + 3) + 1.304x = 56$.$2.304x = 53$.$x = 23$.Number of protons $= 23 + 3 = 26$.The element with atomic number $26$ is Iron $(Fe)$.Thus,the symbol of the ion is $_{26}^{56} Fe^{3+}$.

An ion with mass number $56$ contains $3$ units of positive charge and $30.4 \%$ more neutrons than electrons. Assign the symbol to this ion.

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