An ionic bond P^{+} Q^{-} is most likely to b | vedclass

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(B) The ionization energy $(IE)$ is the energy required to remove an electron from a neutral gaseous atom to form a cation. Lower $IE$ facilitates the

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the ionization energy of $P$ is low and the electron affinity of $Q$ is high

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(B) The ionization energy $(IE)$ is the energy required to remove an electron from a neutral gaseous atom to form a cation. Lower $IE$ facilitates the formation of $P^{+}$. Electron affinity is the energy released when an electron is added to a neutral gaseous atom to form an anion. Higher electron affinity facilitates the formation of $Q^{-}$. Therefore,an ionic bond $P^{+} Q^{-}$ is most likely to be formed when the ionization energy of $P$ is low and the electron affinity of $Q$ is high.

An ionic bond $P^{+} Q^{-}$ is most likely to be formed when

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