An ionic compound A^{+} B^{-} is most likely | vedclass

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(B) The ionization energy $(IE)$ is the energy required to remove an electron from a neutral gaseous atom to form a cation. Lower $IE$ facilitates the

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the ionization energy of $A$ is low and electron affinity of $B$ is high

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(B) The ionization energy $(IE)$ is the energy required to remove an electron from a neutral gaseous atom to form a cation. Lower $IE$ facilitates the formation of $A^{+}$. Electron affinity $(EA)$ is the energy released when an electron is added to a neutral gaseous atom to form an anion. Higher $EA$ facilitates the formation of $B^{-}$. Therefore,for the formation of an ionic compound $A^{+} B^{-}$,the ionization energy of $A$ should be low and the electron affinity of $B$ should be high.

An ionic compound $A^{+} B^{-}$ is most likely to be formed when

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