An ionic compound is expected to have a tetra | vedclass

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(B) The structure of an ionic compound is determined by the radius ratio of the cation to the anion $(r_{+} / r_{-})$. Based on the standard radius ra

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$0.225$ to $0.414$

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(B) The structure of an ionic compound is determined by the radius ratio of the cation to the anion $(r_{+} / r_{-})$. Based on the standard radius ratio rules for coordination geometry:- For $r_{+} / r_{-} - For $0.155 - 0.225$,the structure is planar triangular.- For $0.225 - 0.414$,the structure is tetrahedral.- For $0.414 - 0.732$,the structure is octahedral.- For $0.732 - 1$,the structure is body-centered cubic $(bcc)$.Therefore,the tetrahedral structure corresponds to the range $0.225$ to $0.414$.

An ionic compound is expected to have a tetrahedral structure if the radius ratio $r_{+} / r_{-}$ lies in the range of:

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