An iron rod of length L and magnetic moment M | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The magnetic moment of a rod is given by $M = m 	imes L$,where $m$ is the pole strength and $L$ is the length of the rod.When the rod is bent int

Vedclass · Accepted Answer

$\frac{2M}{\pi}$

Vedclass · Answer

(B) The magnetic moment of a rod is given by $M = m 	imes L$,where $m$ is the pole strength and $L$ is the length of the rod.When the rod is bent into a semicircle,the length $L$ becomes the arc length of the semicircle,so $L = \pi R$,where $R$ is the radius of the semicircle.Thus,the radius $R = \frac{L}{\pi}$.The new distance between the poles (the diameter of the semicircle) is $L' = 2R = \frac{2L}{\pi}$.The pole strength $m$ remains unchanged.Therefore,the new magnetic moment $M'$ is given by $M' = m 	imes L' = m 	imes \frac{2L}{\pi}$.Since $M = m 	imes L$,we can substitute $M$ into the equation:$M' = \frac{2M}{\pi}$.

An iron rod of length $L$ and magnetic moment $M$ is bent in the form of a semicircle. Now its magnetic moment will be

Similar Questions

The magnetic field due to a short bar magnet of magnetic dipole moment $M$ and length $2l$,on the axis at a distance $Z$ (where $Z \gg l$) from the centre of the magnet is given by . . . . . . .

The time period of a freely suspended magnet is $4 \ s$. If it is broken in length into two equal parts and one part is suspended in the same way,then its time period will be: (in $s$)

The magnetic field lines due to a bar magnet are correctly shown in

$A$ magnetized wire of magnetic moment $M$ and length $l$ is bent in the form of a semicircle of radius $r$. Then its new magnetic moment is:

$A$ permanent magnet:

Vedclass Test Series

Exam Paper Generator

Online Exam Module