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(C) Given: Object distance $u = -18 \ cm$ (in front of the mirror).Image distance $v = +4 \ cm$ (on the other side of the mirror).Using the mirror for

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$5.14 \ cm$,convex mirror and virtual image

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(C) Given: Object distance $u = -18 \ cm$ (in front of the mirror).Image distance $v = +4 \ cm$ (on the other side of the mirror).Using the mirror formula: $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$.Substituting the values: $\frac{1}{f} = \frac{1}{4} + \frac{1}{-18} = \frac{9 - 2}{36} = \frac{7}{36}$.Therefore,$f = \frac{36}{7} \ cm \approx 5.14 \ cm$.Since the focal length $f$ is positive,the mirror is a convex mirror.Since the image is formed on the other side of the mirror,it is a virtual image.

An object is placed at a distance of $18 \ cm$ in front of a mirror. If the image is formed at a distance of $4 \ cm$ on the other side,then the focal length,nature of the mirror,and nature of the image are respectively:

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