An object of mass m is moving with a constant | vedclass

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(C) The object is in motion,so its initial kinetic energy is $K_i = 1/2 mv^2$.When the object comes to rest,its final velocity becomes $0$,so its fina

Vedclass · Accepted Answer

$-1/2 mv^2$

Vedclass · Answer

(C) The object is in motion,so its initial kinetic energy is $K_i = 1/2 mv^2$.When the object comes to rest,its final velocity becomes $0$,so its final kinetic energy is $K_f = 0$.According to the work-energy theorem,the work done on an object is equal to the change in its kinetic energy.Work done $W = K_f - K_i$.$W = 0 - 1/2 mv^2 = -1/2 mv^2$.The negative sign indicates that the work is done against the direction of motion to bring the object to rest. The magnitude of the work required is $1/2 mv^2$.

An object of mass $m$ is moving with a constant velocity $v$. How much work should be done on the object in order to bring the object to rest?

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