An object of mass 40, kg is raised to a heigh | vedclass

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Question

(B) We know that,potential energy $(PE) = mgh$.Given:Mass $(m) = 40\, kg$Acceleration due to gravity $(g) = 9.8\, m/s^2$Height $(h) = 5\, m$Potential

Vedclass · Accepted Answer

$1960\, J, 980\, J$

Vedclass · Answer

(B) We know that,potential energy $(PE) = mgh$.Given:Mass $(m) = 40\, kg$Acceleration due to gravity $(g) = 9.8\, m/s^2$Height $(h) = 5\, m$Potential energy $= 40 	imes 9.8 	imes 5 = 1960\, J$.According to the law of conservation of energy,the total mechanical energy remains constant.When the object is half-way down,it has fallen a distance of $2.5\, m$. At this point,half of the initial potential energy is converted into kinetic energy.Therefore,kinetic energy $= 1/2 	imes 1960\, J = 980\, J$.

An object of mass $40\, kg$ is raised to a height of $5\, m$ above the ground. What is its potential energy? If the object is allowed to fall,find its kinetic energy when it is half-way down.

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