An object of mass 4.237 , g occupies a volume | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given mass $m = 4.237 \, g$ (which has $4$ significant figures).Given volume $V = 1.72 \, cm^3$ (which has $3$ significant figures).Density $\rho

Vedclass · Accepted Answer

$2.46$

Vedclass · Answer

(A) Given mass $m = 4.237 \, g$ (which has $4$ significant figures).Given volume $V = 1.72 \, cm^3$ (which has $3$ significant figures).Density $\rho = \frac{m}{V} = \frac{4.237 \, g}{1.72 \, cm^3} \approx 2.46337 \, g \, cm^{-3}$.According to the rules of significant figures,the result of division should have the same number of significant figures as the measurement with the least number of significant figures.Since $1.72$ has $3$ significant figures,the final answer must be rounded to $3$ significant figures.Therefore,the density is $2.46 \, g \, cm^{-3}$.

An object of mass $4.237 \, g$ occupies a volume of $1.72 \, cm^3$. The density of the object to appropriate significant figures is ......... $g \, cm^{-3}$.

Similar Questions

$Assertion$ : The number of significant figures depends on the least count of the measuring instrument.
$Reason$ : Significant figures define the accuracy of the measuring instrument.

$A$ cube has a side of length $1.2 \times 10^{-2} \; m$. Calculate its volume.

The diameter of a wire is measured to be $0.0205 \times 10^{-4} \,m$. The number of significant figures in the measurement is

If the value of resistance is $10.845 \, \Omega$ and the value of current is $3.23 \, \text{A}$,the value of potential with significant figures would be ........... $V$.

The length and breadth of a metal sheet are $3.124\,m$ and $3.002\,m$. The area of the sheet is: (in $,m^2$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module