An octahedral complex with the formula CoCl_3 | vedclass

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(C) The reaction of the complex with excess $AgNO_3$ yields $2$ moles of $AgCl$,which indicates that there are $2$ chloride ions outside the coordinat

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(C) The reaction of the complex with excess $AgNO_3$ yields $2$ moles of $AgCl$,which indicates that there are $2$ chloride ions outside the coordination sphere.The formula of the complex is $[Co(NH_3)_nCl]Cl_2$.Since the complex is octahedral,the coordination number of $Co$ is $6$. Thus,$n + 1 = 6$,which gives $n = 5$.The complex is $[Co(NH_3)_5Cl]Cl_2$.Let the oxidation state of $Co$ be $x$. The sum of oxidation states in the complex is $x + 5(0) + 1(-1) + 2(-1) = 0$,which gives $x - 3 = 0$,so $x = +3$.Therefore,$x + n = 3 + 5 = 8$.

An octahedral complex with the formula $CoCl_3 \cdot nNH_3$ upon reaction with excess of $AgNO_3$ solution gives $2$ moles of $AgCl$. Consider the oxidation state of $Co$ in the complex is '$x$'. The value of $x+n$ is . . . . .

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