An open U-tube contains mercury. When 13.6 ,c | vedclass

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(B) Let the density of water be $\rho_w = 1 \,g/cm^3$ and the density of mercury be $\rho_m = 13.6 \,g/cm^3$.When water of height $h_w = 13.6 \,cm$ is

Vedclass · Accepted Answer

$0.5$

Vedclass · Answer

(B) Let the density of water be $ho_w = 1 \,g/cm^3$ and the density of mercury be $ho_m = 13.6 \,g/cm^3$.When water of height $h_w = 13.6 \,cm$ is poured into one arm,the mercury level in that arm drops by $y$,and it rises by $y$ in the other arm.The difference in the mercury levels between the two arms becomes $2y$.According to the principle of hydrostatic pressure at the same horizontal level:$P_{	ext{water}} = P_{	ext{mercury}}$$ho_w \cdot g \cdot h_w = ho_m \cdot g \cdot (2y)$Substituting the values:$1 \cdot g \cdot 13.6 = 13.6 \cdot g \cdot (2y)$$13.6 = 13.6 \cdot 2y$$2y = 1$$y = 0.5 \,cm$Therefore,the mercury rises by $0.5 \,cm$ in the other arm.

An open $U$-tube contains mercury. When $13.6 \,cm$ of water is poured into one of the arms of the tube,then the mercury rise in the other arm from its initial level is ....... $cm$

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