An open box is made of wood 2, cm thick. Its | vedclass

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(D) Internal dimensions: $L = 86\, cm, B = 46\, cm, H = 38\, cm.$Since the box is open at the top and made of $2\, cm$ thick wood:External length $= 8

Vedclass · Accepted Answer

$15.7$

Vedclass · Answer

(D) Internal dimensions: $L = 86\, cm, B = 46\, cm, H = 38\, cm.$Since the box is open at the top and made of $2\, cm$ thick wood:External length $= 86 + 2 + 2 = 90\, cm = 0.9\, m.$External breadth $= 46 + 2 + 2 = 50\, cm = 0.5\, m.$External height $= 38 + 2 = 40\, cm = 0.4\, m$ (only bottom is added).Outer surface area of an open box $= (2 	imes 	ext{External Height} 	imes (	ext{External Length} + 	ext{External Breadth})) + (	ext{External Length} 	imes 	ext{External Breadth})$.Area $= (2 	imes 0.4 	imes (0.9 + 0.5)) + (0.9 	imes 0.5) = (0.8 	imes 1.4) + 0.45 = 1.12 + 0.45 = 1.57\, m^2$.Cost of painting $= 1.57\, m^2 	imes 10\, Rs./m^2 = 15.7\, Rs.$

An open box is made of wood $2\, cm$ thick. Its internal length is $86\, cm,$ breadth $46\, cm$ and height is $38\, cm.$ The cost of painting the outer surface of the box at $Rs.$ $10$ per $m^2$ is? (in $Rs.$)

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