An open vessel at 300 K is heated until 2/5 | vedclass

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(C) Let the volume of the vessel be $V$. Initially,the volume of air at $T_1 = 300 \ K$ is $V$.Since $2/5$ of the air is expelled,the remaining volume

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$500$

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(C) Let the volume of the vessel be $V$. Initially,the volume of air at $T_1 = 300 \ K$ is $V$.Since $2/5$ of the air is expelled,the remaining volume of air at $300 \ K$ is $V - (2/5)V = (3/5)V$.When the vessel is heated to a new temperature $T_2$,this remaining air expands to fill the entire volume $V$ of the vessel.Since the pressure remains constant in an open vessel,we use Charles's Law: $\frac{V_1}{T_1} = \frac{V_2}{T_2}$.Substituting the values: $\frac{(3/5)V}{300} = \frac{V}{T_2}$.Solving for $T_2$: $T_2 = 300 	imes \frac{5}{3} = 500 \ K$.

An open vessel at $300 \ K$ is heated until $2/5$ of the air in it is expelled. Assuming that the volume of the vessel remains constant,the temperature to which the vessel is heated is $..... \ K$.

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