An optically active alkyl bromide C_4H_9Br re | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The optically active alkyl bromide $C_4H_9Br$ is $2$-bromobutane.Reaction of $2$-bromobutane with ethanolic $KOH$ (dehydrohalogenation) gives but-

Vedclass · Accepted Answer

Haloform test

Vedclass · Answer

(A) The optically active alkyl bromide $C_4H_9Br$ is $2$-bromobutane.Reaction of $2$-bromobutane with ethanolic $KOH$ (dehydrohalogenation) gives but-$2$-ene as the major product $[A]$.Reaction of but-$2$-ene $[A]$ with $Br_2$ yields $2,3$-dibromobutane $[B]$.Reaction of $2,3$-dibromobutane $[B]$ with alcoholic $KOH$ followed by $NaNH_2$ (dehydrohalogenation) yields but-$2$-yne $[C]$.Hydration of but-$2$-yne $[C]$ in the presence of $HgSO_4/H_2SO_4$ (Kucherov's reaction) yields butanone $(CH_3COCH_2CH_3)$, which is a methyl ketone.Methyl ketones are confirmed by the Haloform test (specifically the Iodoform test).

$I. HNO_3$	$II. NH_2NH_2 / OH^-$
$III. 2[Ag(NH_3)_2]^+$	$IV. NaOH$

Similar Questions

Which of the following reagents will convert isobutyraldehyde to the corresponding acid?
$I. HNO_3$ $II. NH_2NH_2 / OH^-$
$III. 2[Ag(NH_3)_2]^+$ $IV. NaOH$

Identify the reagent used in the transformation of a ketone into a semicarbazone.

Identify $A$ and $B$ in the given reaction sequence:
Cyclohexylidene ethyl acetate $\xrightarrow{A}$ Cyclohexylidene ethanol $\xrightarrow{MnO_2} B$

$2(CHO-COOH) \xrightarrow{NaOH} CH_2OH-COOH + HOOC-COONa$. This reaction is:

The synthesis of crotonaldehyde from acetaldehyde is an example of ....... reaction.

Vedclass Test Series

Exam Paper Generator

Online Exam Module