An organ pipe with both ends open has a length $L=25 \,cm$. An extra hole is created at position $\frac{L}{2}$. The lowest frequency of sound produced is (assume, speed of sound $=340 \,m/s$) (in $\,Hz$)

Two closed pipes produce $10$ beats per second when emitting their fundamental notes. If their lengths are in the ratio of $25 : 26$,then their fundamental frequencies in $Hz$ are:

The ratio of the frequencies of the fundamental harmonic produced by an open pipe to that of a closed pipe having the same length is

$A$ tuning fork vibrates with frequency $256\, Hz$ and gives one beat per second with the third normal mode of vibration of an open pipe. What is the length of the pipe in $cm$? (Speed of sound in air is $340\, m/s$)

If the length of a closed organ pipe is $1 \ m$ and the velocity of sound is $330 \ m/s$,then the frequency for the second note (first overtone) is:

$A$ metre-long tube open at one end,with a movable piston at the other end,shows resonance with a fixed frequency source (a tuning fork of frequency $340\; Hz$) when the tube length is $25.5\; cm$ or $79.3\; cm$. Estimate the speed of sound (in $m/s$) in air at the temperature of the experiment. The edge effects may be neglected.