An organic compound A on reaction with NH_{3} | vedclass

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(C) The reaction sequence described is the Gabriel phthalimide synthesis. \ $1$. Compound $A$ is phthalic acid $(C_{6}H_{4}(COOH)_{2})$. \ $2$. Reac

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Phthalic acid

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(C) The reaction sequence described is the Gabriel phthalimide synthesis. \ $1$. Compound $A$ is phthalic acid $(C_{6}H_{4}(COOH)_{2})$. \ $2$. Reaction of phthalic acid with $NH_{3}$ followed by heating gives phthalimide $(C_{8}H_{5}NO_{2})$,which is compound $C$. The intermediate $B$ is phthalamide $(C_{6}H_{4}(CONH_{2})_{2})$. \ $3$. Phthalimide $(C)$ reacts with ethanolic $KOH$ to form potassium phthalimide. \ $4$. Potassium phthalimide reacts with alkyl chloride $(R-Cl)$ via $S_{N}2$ mechanism to form $N$-alkylphthalimide. \ $5$. Hydrolysis of $N$-alkylphthalimide with alkali gives a primary amine $(RNH_{2})$ and phthalic acid. \ Thus,compound $A$ is phthalic acid.

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