An organic compound [A] (C_4H_{11}N) shows op | vedclass

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(D) $1$. The molecular formula $C_4H_{11}N$ corresponds to a saturated amine.$2$. The reaction with $HNO_2$ to release $N_2$ gas indicates that the co

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Butan$-2-$amine

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(D) $1$. The molecular formula $C_4H_{11}N$ corresponds to a saturated amine.$2$. The reaction with $HNO_2$ to release $N_2$ gas indicates that the compound is a primary aliphatic amine $(R-NH_2)$.$3$. The reaction with $PhSO_2Cl$ (Hinsberg reagent) produces a sulfonamide that is soluble in $KOH$. This confirms that the amine is a primary amine,as the resulting sulfonamide contains an acidic hydrogen on the nitrogen atom.$4$. The compound must be optically active. Among the primary amines with the formula $C_4H_{11}N$,butan$-2-$amine $(CH_3CH_2CH(NH_2)CH_3)$ contains a chiral carbon atom and is therefore optically active.$5$. Butan$-1-$amine is achiral.

An organic compound $[A]$ $(C_4H_{11}N)$ shows optical activity and gives $N_2$ gas on treatment with $HNO_2$. The compound $[A]$ reacts with $PhSO_2Cl$ producing a compound which is soluble in $KOH$. The structure of $A$ is:

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