An organic compound $CH_3-CH=CH-CH_2-CHO$ is taken in two different containers $A$ and $B$. Sample in $A$ is treated with $H_2 / Ni$ forming new compound $P$. Sample in $B$ is treated with $LiAlH_4$ and hydrolyzed further forming new compound $Q$. Identify $P$ and $Q$.

  • A
    $P = Q = CH_3-CH=CH-CH_2-CH_2OH$
  • B
    $P = Q = CH_3(CH_2)_3CH_2OH$
  • C
    $P = CH_3(CH_2)_3CHO$ and $Q = CH_3(CH_2)_3CH_2OH$
  • D
    $P = CH_3(CH_2)_3CH_2OH$ and $Q = CH_3-CH=CH-CH_2-CH_2OH$

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