An organic compound of molecular formula C_6H | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The molecular formula is $C_6H_6Br_2$.Double bond equivalent $(DBU)$ formula $= C - \frac{H}{2} - \frac{X}{2} + 1$.For $C=6, H=6, X=2$:$DBU = 6 -

Vedclass · Accepted Answer

homo-cyclic but not aromatic

Vedclass · Answer

(C) The molecular formula is $C_6H_6Br_2$.Double bond equivalent $(DBU)$ formula $= C - \frac{H}{2} - \frac{X}{2} + 1$.For $C=6, H=6, X=2$:$DBU = 6 - \frac{6}{2} - \frac{2}{2} + 1 = 6 - 3 - 1 + 1 = 3$.This indicates the presence of one ring and two double bonds.The structure consists of a six-membered carbon ring (homo-cyclic) with two non-conjugated double bonds and two bromo groups at the $1,4$ positions.Since it does not satisfy $H$ückel's rule ($4n+2$ $\pi$ electrons in a planar,fully conjugated system),it is not aromatic.Therefore,the compound is homo-cyclic but not aromatic.

An organic compound of molecular formula $C_6H_6Br_2$ has six carbon atoms in a ring system,two non-conjugate double bonds and two bromo groups at $1,4$ positions. Then the compound is

Similar Questions

Which of the following compounds has the maximum number of hydrogen atoms?

Explain acyclic or open chain compounds with examples.

Which of the following compounds contains oxygen as a heteroatom?

Provide the classification of organic compounds.

Which of the following is a heterocyclic compound?

Vedclass Test Series

Exam Paper Generator

Online Exam Module