An organic compound on analysis gave C = 48 , | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Step $1$: Determine the empirical formula.ElementMass $(g)$MolesSimple Ratio$C$$48$$48/12 = 4$$1$$H$$8$$8/1 = 8$$2$$N$$56$$56/14 = 4$$1$Empirical

Vedclass · Accepted Answer

$C_4H_8N_4$

Vedclass · Answer

(A) Step $1$: Determine the empirical formula.ElementMass $(g)$MolesSimple Ratio$C$$48$$48/12 = 4$$1$$H$$8$$8/1 = 8$$2$$N$$56$$56/14 = 4$$1$Empirical formula = $CH_2N$.Empirical formula mass = $12 + 2(1) + 14 = 28 \,g/mol$.Step $2$: Determine the molar mass.At $NTP$, $22400 \,mL$ of gas corresponds to $1 \,mole$.Given $200 \,mL$ of the compound weighs $1 \,g$.Therefore, $22400 \,mL$ weighs $\frac{1}{200} 	imes 22400 = 112 \,g$.Molar mass = $112 \,g/mol$.Step $3$: Calculate the molecular formula.$n = \frac{	ext{Molar mass}}{	ext{Empirical formula mass}} = \frac{112}{28} = 4$.Molecular formula = $n 	imes (CH_2N) = 4 	imes (CH_2N) = C_4H_8N_4$.

An organic compound on analysis gave $C = 48 \,g$, $H = 8 \,g$ and $N = 56 \,g$. The volume of $1.0 \,g$ of the compound was found to be $200 \,mL$ at $NTP$. What is the molecular formula of the compound?

Similar Questions

$0.01 \ mol$ of an organic compound $(X)$ containing $10\%$ hydrogen,on complete combustion produced $0.9 \ g \ H_2O$. Molar mass of $(X)$ is $.......... \ g \ mol^{-1}$.

$A$ compound contains $8\%$ sulfur by weight. The minimum molecular weight of the compound is:

Reduction of $7.2 \, g$ of a metal oxide yields $6.4 \, g$ of the metal. If the atomic mass of the metal is $128 \, g/mol$,the formula of the oxide is .....

The molecular formula of a compound is $X_4O_6$. If $10 \ g$ of the compound contains $5.62 \ g$ of $X$,what is the approximate atomic mass of $X$ in $amu$?

$0.102 \ g$ of an organic compound $X$ was oxidised with fuming nitric acid. The resulting solution,after reaction with excess of aqueous $BaCl_2$,produced $0.233 \ g$ of $BaSO_4$ as a precipitate. Compound $X$ is likely to be: [Given: Atomic wt. of $Ba = 137$]

Vedclass Test Series

Exam Paper Generator

Online Exam Module