An organic compound on analysis gave the foll | vedclass

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Question

(A) To find the empirical formula,we calculate the mole ratio of each element:            Element      Percentage / Atomic Mass      Moles      Simple

Vedclass · Accepted Answer

$C_2H_4O$

Vedclass · Answer

(A) To find the empirical formula,we calculate the mole ratio of each element:            Element      Percentage / Atomic Mass      Moles      Simple Ratio                  $C$      $54.5 / 12$      $4.54$      $4.54 / 2.27 = 2$              $H$      $9.1 / 1$      $9.1$      $9.1 / 2.27 = 4$              $O$      $36.4 / 16$      $2.27$      $2.27 / 2.27 = 1$      The ratio of $C:H:O$ is $2:4:1$. Therefore,the empirical formula is $C_2H_4O$.

An organic compound on analysis gave the following results: $C = 54.5\%$,$O = 36.4\%$,$H = 9.1\%$. The empirical formula of the compound is:

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