An unknown nucleus has a nuclear density of 2 | vedclass

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(C) The mass of a nucleus is given by $M = A 	imes m_p$, where $A$ is the mass number and $m_p$ is the average mass of a nucleon (approximately $1.67

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$12$

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(C) The mass of a nucleus is given by $M = A 	imes m_p$, where $A$ is the mass number and $m_p$ is the average mass of a nucleon (approximately $1.67 	imes 10^{-27} 	ext{ kg}$).Given the total mass of the nucleus $M = 19.926 	imes 10^{-27} 	ext{ kg}$.We can calculate the mass number $A$ as:$A = \frac{M}{m_p} = \frac{19.926 	imes 10^{-27} 	ext{ kg}}{1.67 	imes 10^{-27} 	ext{ kg}} \approx 11.93$.Rounding this value to the nearest integer, we get $A \approx 12$.Thus, the mass number of the nucleus is $12$.

An unknown nucleus has a nuclear density of $2.29 \times 10^{17} \text{ kg/m}^3$ and mass of $19.926 \times 10^{-27} \text{ kg}$. Its mass number $A$ is approximately: (Take $R_0 = 1.2 \times 10^{-15} \text{ m}$, $4\pi = 12.56$)

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