An unknown resistance R_1 is connected in ser | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In a meter bridge,the balancing condition is given by $\frac{P}{Q} = \frac{l}{100-l}$,where $P$ and $Q$ are resistances in the two gaps and $l$ is

Vedclass · Accepted Answer

$20$

Vedclass · Answer

(C) In a meter bridge,the balancing condition is given by $\frac{P}{Q} = \frac{l}{100-l}$,where $P$ and $Q$ are resistances in the two gaps and $l$ is the balance length.Case $1$: $R_1$ is in series with $10 \,\Omega$ in one gap,and $R_2$ is in the other gap. The balance point is at $50 \, cm$.$\frac{R_1 + 10}{R_2} = \frac{50}{100-50} = \frac{50}{50} = 1$$\Rightarrow R_2 = R_1 + 10$  --- (Equation $1$)Case $2$: The $10 \,\Omega$ resistance is removed,so only $R_1$ remains in the first gap. The balance point shifts to $40 \, cm$.$\frac{R_1}{R_2} = \frac{40}{100-40} = \frac{40}{60} = \frac{2}{3}$$\Rightarrow 3R_1 = 2R_2$ --- (Equation $2$)Substitute Equation $1$ into Equation $2$:$3R_1 = 2(R_1 + 10)$$3R_1 = 2R_1 + 20$$R_1 = 20 \,\Omega$.

Similar Questions

The meter bridge shown is in a balanced position with $\frac{P}{Q} = \frac{l_{1}}{l_{2}}$. If we now interchange the positions of the galvanometer and the cell,will the bridge work? If yes,what will be the balance condition?

In the shown arrangement of the meter bridge experiment,if the length $AC$ corresponding to the null deflection of the galvanometer is $x$,what would be its value if the radius of the wire $AB$ is doubled?

In a metre bridge experiment (see figure), the positions of the cell, $E$, and galvanometer, $G$, are interchanged. We shall observe in the galvanometer:

In a meter bridge,the two gaps contain resistances of $10 \, \Omega$ and $30 \, \Omega$ respectively. If these resistances are interchanged,the null point shifts by ..... cm.

Vedclass Test Series

Exam Paper Generator

Online Exam Module