An unpolarized light of average intensity I i | vedclass

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(B) When unpolarized light of intensity $I$ passes through a polarizer,the intensity of the transmitted light becomes $I' = \frac{I}{2}$.The relations

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$\sqrt{\frac{I}{c\epsilon_0}}$

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(B) When unpolarized light of intensity $I$ passes through a polarizer,the intensity of the transmitted light becomes $I' = \frac{I}{2}$.The relationship between the intensity $I'$ and the amplitude of the electric field $E_0$ of an electromagnetic wave is given by $I' = \frac{1}{2} c \epsilon_0 E_0^2$.Substituting $I' = \frac{I}{2}$ into the formula:$\frac{I}{2} = \frac{1}{2} c \epsilon_0 E_0^2$Solving for $E_0$:$I = c \epsilon_0 E_0^2$$E_0^2 = \frac{I}{c \epsilon_0}$$E_0 = \sqrt{\frac{I}{c \epsilon_0}}$

An unpolarized light of average intensity $I$ is passed through a polarizer. Find the amplitude of electric field of light coming out. (Symbols have their usual meaning)

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