An urn contains $9$ balls of which $3$ are red,$4$ are blue and $2$ are green. Three balls are drawn at random from the urn. The probability that the three balls have different colours is
- A$\frac{1}{14}$
- B$\frac{3}{14}$
- C$\frac{1}{7}$
- D$\frac{2}{7}$
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