Aniline is treated with NaNO_2 + HCl at low t | vedclass

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(D) When aniline $(C_6H_5NH_2)$ reacts with nitrous acid $(HNO_2)$,which is generated in situ by the reaction of $NaNO_2$ and $HCl$ at a low temperatu

Vedclass · Accepted Answer

Benzenediazonium chloride

Vedclass · Answer

(D) When aniline $(C_6H_5NH_2)$ reacts with nitrous acid $(HNO_2)$,which is generated in situ by the reaction of $NaNO_2$ and $HCl$ at a low temperature of $273-278 \ K$,it undergoes a diazotization reaction. This reaction converts the amino group $(-NH_2)$ into a diazonium group $(-N_2^+Cl^-)$,resulting in the formation of benzenediazonium chloride $(C_6H_5N_2^+Cl^-)$.

Aniline is treated with $NaNO_2 + HCl$ at low temperature to form:

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