Aniline under acidic medium,when chlorinated, | vedclass

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Question

(B) In an acidic medium,aniline $(C_6H_5NH_2)$ gets protonated to form the anilinium ion $(C_6H_5NH_3^+)$. The $-NH_3^+$ group is meta-directing becau

Vedclass · Accepted Answer

$m-$chloroaniline

Vedclass · Answer

(B) In an acidic medium,aniline $(C_6H_5NH_2)$ gets protonated to form the anilinium ion $(C_6H_5NH_3^+)$. The $-NH_3^+$ group is meta-directing because it is strongly electron-withdrawing due to the positive charge on the nitrogen atom. Consequently,the electrophilic substitution (chlorination) occurs primarily at the meta-position. Therefore,the major product formed is $m-$chloroaniline.

Aniline under acidic medium,when chlorinated,produces :

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