Aqueous solution of a metallic nitrate $X$ reacts with $NH_4OH$ to form $Y$,which dissolves in excess $NH_4OH$. The resulting complex is reduced by acetaldehyde to deposit the metal. $X$ and $Y$,respectively,are
- A$Cs(NO_3)$ and $CsOH$
- B$Zn(NO_3)_2$ and $ZnO$
- C$AgNO_3$ and $Ag_2O$
- D$Mg(NO_3)_2$ and $Mg(OH)_2$
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