Are all the five bonds in $PCl_{5}$ molecule equivalent? Justify your answer.
(N/A) $PCl_{5}$ has a trigonal bipyramidal geometry. In this structure,the three equatorial $P-Cl$ bonds are at $120^{\circ}$ to each other,while the two axial $P-Cl$ bonds are at $90^{\circ}$ to the equatorial plane. Due to greater repulsion from the equatorial bond pairs,the axial bonds are longer and weaker than the equatorial bonds. Therefore,all five bonds in $PCl_{5}$ are not equivalent.
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(Image provided)
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(Image provided)
Statement $(II) :$ Structure $III$ is most stable,as the orbitals having the lone pairs are axial,where the $\ell p-bp$ repulsion is minimum.
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