Area of a right triangle $=$ ...........
- A$\frac{3}{2} \times$ product of the sides forming the right angle
- B$\frac{1}{2} \times$ product of the sides forming the right angle
- C$\frac{1}{5} \times$ product of the sides forming the right angle
- D$\frac{1}{3} \times$ product of the sides forming the right angle
Explore More
Similar Questions
In the figure,$PQ > PR$ and $QS$ and $RS$ are the bisectors of $\angle Q$ and $\angle R$,respectively. Show that $SQ > SR$.
Easy
View SolutionIn $\Delta ABC$,$\angle B = 90^{\circ}$ and $BM$ is an altitude to the hypotenuse $AC$. If $AB = 12 \, cm$ and $BC = 16 \, cm$,then find the length of $BM$ in $cm$.
Medium
View SolutionShow that in a right-angled triangle,the hypotenuse is the longest side.
Difficult
View SolutionProve that the sum of any two sides of a triangle is greater than twice the median with respect to the third side.
Medium
View SolutionIn $\Delta ABC$,$\angle A : \angle B : \angle C = 5 : 7 : 8$. Find the measure of each angle of $\Delta ABC$.
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo