Arrange N,O,and S in order of decreasing elec | vedclass

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(A) The electron affinity of elements generally increases across a period and decreases down a group.For the given elements,$N$ has a stable half-fill

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$S > O > N$

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(A) The electron affinity of elements generally increases across a period and decreases down a group.For the given elements,$N$ has a stable half-filled $2p^3$ configuration,making its electron affinity very low (near zero or negative).Oxygen $(O)$ has a smaller size,which leads to significant inter-electronic repulsion when an electron is added to its $2p$ orbital,resulting in a lower electron affinity compared to Sulfur $(S)$.Sulfur $(S)$ has a larger $3p$ orbital,which reduces inter-electronic repulsion,giving it the highest electron affinity among the three.Therefore,the correct order of decreasing electron affinity is $S > O > N$.

Arrange $N$,$O$,and $S$ in order of decreasing electron affinity.

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