Arrange the following polymers in the decreas | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The strength of intermolecular forces in polymers follows the order: $	ext{Thermosetting polymers} > 	ext{Fibres} > 	ext{Thermoplastics} > 	ex

Vedclass · Accepted Answer

$A > D > B > C$

Vedclass · Answer

(B) The strength of intermolecular forces in polymers follows the order: $	ext{Thermosetting polymers} > 	ext{Fibres} > 	ext{Thermoplastics} > 	ext{Elastomers}$.$1$. Bakelite is a thermosetting polymer,which has the strongest intermolecular forces due to cross-linking.$2$. Nylon-$6,6$ is a fibre,which has strong hydrogen bonding (dipole-dipole interactions).$3$. Teflon (Polytetrafluoroethylene) is a thermoplastic,which has intermediate forces.$4$. Buna-$S$ is an elastomer,which has the weakest intermolecular forces.Therefore,the correct decreasing order is: Bakelite $(A)$ $>$ Nylon-$6,6$ $(D)$ $>$ Teflon $(B)$ $>$ Buna-$S$ $(C)$.

Arrange the following polymers in the decreasing order of their intermolecular forces:
$A$. Bakelite
$B$. Teflon
$C$. Buna-$S$
$D$. Nylon-$6,6$

Similar Questions

Which of the following is the first stage in the preparation of viscose rayon?

Which of the following is an example of a thermosetting polymer?

Nylon threads are made from which polymer?

Which among the following polymers is obtained from styrene and $1,3-$Butadiene?

Which of the following intermolecular forces are present in $nylon-66$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Arrange the following polymers in the decreasing order of their intermolecular forces:$A$. Bakelite$B$. Teflon$C$. Buna-$S$$D$. Nylon-$6,6$