Arrange the aqueous solutions of the followin | vedclass

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(A) The $pH$ of the solutions depends on the nature of the salt:$I$. $CuSO_4$ is a salt of a strong acid $(H_2SO_4)$ and a weak base $(Cu(OH)_2)$,so i

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$I < III < II$

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(A) The $pH$ of the solutions depends on the nature of the salt:$I$. $CuSO_4$ is a salt of a strong acid $(H_2SO_4)$ and a weak base $(Cu(OH)_2)$,so its aqueous solution is acidic $(pH $II$. $NaCN$ is a salt of a weak acid $(HCN)$ and a strong base $(NaOH)$,so its aqueous solution is basic $(pH > 7)$.$III$. $KCl$ is a salt of a strong acid $(HCl)$ and a strong base $(KOH)$,so its aqueous solution is neutral $(pH = 7)$.Therefore,the increasing order of $pH$ is $I < III < II$.

Arrange the aqueous solutions of the following salts in the increasing order of their $pH$.
$I$. $CuSO_4$
$II$. $NaCN$
$III$. $KCl$

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Arrange the aqueous solutions of the following salts in the increasing order of their $pH$.$I$. $CuSO_4$$II$. $NaCN$$III$. $KCl$