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(A) The reactivity of carbonyl compounds toward nucleophilic attack by $LiAlH_4$ depends on the electrophilicity of the carbonyl carbon.$(i)$ Cyclopen

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$ii < iii < i$

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(A) The reactivity of carbonyl compounds toward nucleophilic attack by $LiAlH_4$ depends on the electrophilicity of the carbonyl carbon.$(i)$ Cyclopentanone is a ketone,which is highly reactive toward nucleophilic attack as there is no resonance stabilization of the carbonyl carbon.(ii) $N$-Methylpyrrolidin$-2-$one is an amide. The lone pair on the nitrogen atom participates in resonance with the carbonyl group ($+M$ effect),significantly reducing the electrophilicity of the carbonyl carbon.(iii) $\gamma$-Butyrolactone is an ester. The lone pair on the oxygen atom participates in resonance with the carbonyl group ($+M$ effect),reducing the electrophilicity of the carbonyl carbon,but to a lesser extent than the amide because oxygen is more electronegative than nitrogen.Thus,the order of reactivity is: Amide $(ii)$ Therefore,the correct order is $ii < iii < i$.

Arrange the following compounds in order of their reactivity toward $LiAlH_4$:
$(i)$ Cyclopentanone
(ii) $N$-Methylpyrrolidin$-2-$one
(iii) $\gamma$-Butyrolactone

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Arrange the following compounds in order of their reactivity toward $LiAlH_4$:$(i)$ Cyclopentanone(ii) $N$-Methylpyrrolidin$-2-$one(iii) $\gamma$-Butyrolactone